Day / Day of the month (day)
Returns the duration representation of 1 day, or the day of the month from a given timestamp and an optional time zone.
How does it work in the search window?
Select Create column in the search window toolbar, then select the Day / day of the month operation.
This operation can be applied with no arguments. In this case, you will get the duration representation of 1 day (duration data type, 1d).
If you add the Timestamp argument, you will get the day of the month considering your current timezone. Optionally, you can specify a different time zone adding the Time zone argument. In both cases, the data type of the new column values will be integer (values 0-30).
Note that the count starts at 0, so the result will be the day - 1 (for example, if the day of the month is 20, you will get 19).
demo.ecommerce.data table, we want to create a column showing the day of the month of the dates in our eventdate column. To do it, we will create a new column using the Day / day of the month operation.
The arguments needed to create the new column are:
- Timestamp - eventdate column
Click Create column and you will see the following result:
How does it work in LINQ?
Use the operator
as... and add the operation syntax to create the new column. These are the valid formats for the Day / day of the month operation:
day()→ Use this expression to get the representation of one day in duration data type (1d).
day(timestamp)→ Use this expression to get the day of the month corresponding to the given timestamps, according to your current time zone.
day(timestamp, timezone_string)→ Use this expression to get the day of the month corresponding to the given timestamps, according to the specified time zone.
You can copy the following LINQ script and try the above example on the
from demo.ecommerce.data select day(eventdate) as eventdate_days